In the saturated solution of
Zr3(PO4)4+aq⇌33S molarZr4++44S molarPO43−
Ksp=[Zr4+]3[PO43−]4=(3S)3(4S)4
=27×256×s7=6912 S7
S=(6912Ksp)1/7
JEE Main 2014 — Chemistry Physical Chemistry
Zirconium phosphate [Zr3(PO4)4] dissociates into three zirconium cations of charge +4 and four phosphate anions of charge −3. If molar solubility of zirconium phosphate is denoted by s and its solubility product by Ksp then which of the following relationship between s and Ksp is correct ?
Held on 19 Apr 2014 · Verified 6 Jul 2026.
S=Ksp/69127
S=Ksp/1441/7
S=Ksp/(6912)1/7
S=(Ksp/6912)1/7
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