Resistance of 0.2 M solution… - JEE Main 2014 Chemistry PYQ

JEE Main 2014 — Chemistry Physical Chemistry

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Resistance of 0.2 M solution of an electrolyte is $5 0 \Omega$ . The specific conductance of the solution is ${\text{1.4 S m}}^{-1}$ . The resistance of 0.5 M solution of the same electrolyte is $28 0 \Omega$ . The molar conductivity of 0.5 M solution of the electrolyte in ${\text{S m}}^{2} {mol}^{-1}$ is :

Official previous-year question

Held on 6 Apr 2014 · Verified 6 Jul 2026.

Options

A
$5 \times 1 {0}^{ - 4 }$
B
$5 \times 1 {0}^{ - 3 }$
C
$5 \times 1 {0}^{ 3 }$
D
$5 \times 1 {0}^{ 2 }$

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Solution

$\text{K} = \frac{ 1 }{ \text{R} } ( \frac{ \text{l} }{ \text{a} } )$

${\text{K}}_{( \text{0.2 M} )} = \frac{ 1 }{ 5 0 } ( \frac{ \text{l} }{ \text{a} } )$ ...... (I)

${\text{K}}_{( \text{0.5 M} )} = \frac{ 1 }{ 28 0 } ( \frac{ \text{l} }{ \text{a} } )$ ...... (II)

$\frac{ {\text{K}}_{( \text{0.5 M} )} }{ {\text{K}}_{( \text{0.2 M} )} } = \frac{ 1 }{ 2 8 0 } \times 5 0$

${\text{K}}_{( \text{0.5 M} )} = \frac{ \text{1.4} }{ 2 8 0 } \times 5 0 = \frac{ 1 }{ 4 }$

${\Lambda }_{\text{m}} = \frac{ \text{K} }{ \text{C} } = \frac{ 1 }{ 4 } \times \frac{ 1 }{ \text{0.5} \times 1 {0}^{3} } = 5 \times 1 {0}^{ - 4 } { \Omega }^{-1} {m}^{2} {\text{mol}}^{-1}$

$( \text{C} = {\text{concentration in mol/m}}^{3} = \text{0.5} \times 1 {0}^{3} {moles/m}^{3} )$

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Solution

$\text{K} = \frac{ 1 }{ \text{R} } ( \frac{ \text{l} }{ \text{a} } )$

${\text{K}}_{( \text{0.2 M} )} = \frac{ 1 }{ 5 0 } ( \frac{ \text{l} }{ \text{a} } )$ ...... (I)

${\text{K}}_{( \text{0.5 M} )} = \frac{ 1 }{ 28 0 } ( \frac{ \text{l} }{ \text{a} } )$ ...... (II)

$\frac{ {\text{K}}_{( \text{0.5 M} )} }{ {\text{K}}_{( \text{0.2 M} )} } = \frac{ 1 }{ 2 8 0 } \times 5 0$

${\text{K}}_{( \text{0.5 M} )} = \frac{ \text{1.4} }{ 2 8 0 } \times 5 0 = \frac{ 1 }{ 4 }$

${\Lambda }_{\text{m}} = \frac{ \text{K} }{ \text{C} } = \frac{ 1 }{ 4 } \times \frac{ 1 }{ \text{0.5} \times 1 {0}^{3} } = 5 \times 1 {0}^{ - 4 } { \Omega }^{-1} {m}^{2} {\text{mol}}^{-1}$

$( \text{C} = {\text{concentration in mol/m}}^{3} = \text{0.5} \times 1 {0}^{3} {moles/m}^{3} )$

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Options

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Solution

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JEE Main Physical Chemistry in other years

More JEE Main Physical Chemistry questions

Other Chemistry topics for JEE Main

Organic Chemistry

Inorganic Chemistry

Keep practicing Physical Chemistry