PT=PX0xX+PY0xYxX= mol fraction of XxY= mol fraction of Y∴550=Px∘(1+31)+PY∘(1+33)=4PX0+43PY0∴550(4)=PX0+3PY0 Further 1 mol of Y is added and total pressure increases by 10 mmHg. ∴550+10=PX∘(1+41)+PY∘(1+44)∴560(5)=PX∘+4PY∘…………(2) By solving (1) and (2) We get, Px∘=400 mmHg PY∘=600 mmHg