Let the density of solution be ' d ' Molarity of solution given =3.6 i.e. 1 litre of solution contains 3.6 moles of H2SO4 or 1 litre of solution contains 3.6×98 gms of H2SO4 Since, the solution is 29% by mass. 100 gm solution contains 29 gm H2SO4 d100ml solution contains 29 gm of H2SO4 1000 ml solution contains 3.6×98 gm of H2SO4 ∴3.6×98=10029×d×1000 d=1.22 Hence, (C) is correct.
The density (in g ~mL^-1 ) of a 3.60 ~M sulphuric acid solution that is 29 % ~ H_2 SO_4 (Molar mass =98 ~g mol^-1 ) by mass will be
JEE Main 2007 — Chemistry Physical Chemistry
The density (in g mL−1 ) of a 3.60 M sulphuric acid solution that is 29% H2SO4 (Molar mass =98 g mol−1 ) by mass will be
Held on 30 Apr 2007 · Verified 6 Jul 2026.
Options
- A
1.64
- B
1.88
- C
1.22
- D
1.45
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