2CuSO4+K4[Fe(CN)6]CH3COOH(Chocolate brown ppt.)Cu2[Fe(CN)6]+2 K2SO4
4FeCl3+3 K4[Fe(CN)6]⟶ (Prussian Blue ppt.) Fe4[Fe(CN)6]3+12KCl
3ZnCl4+2 K4[Fe(CN)6]NH4OH (White or bluish white ppt.) K2Zn3[Fe(CN)6]2+6KCl
JEE Main 2025 — Chemistry Inorganic Chemistry
Choose the correct tests with respective observations.
(A) CuSO4 (acidified with acetic acid) +K4[Fe(CN)6]→ Chocolate brown precipitate.
(B) FeCl3+K4[Fe(CN)6]→ Prussian blue precipitate.
(C) ZnCl2+K4[Fe(CN)6], neutralised with NH4OH → White or bluish white precipitate.
(D) MgCl2+K4[Fe(CN)6]→ Blue precipitate.
(E) BaCl2+K4[Fe(CN)6], neutralised with NaOH → White precipitate.
Choose the correct answer from the options given below :
Held on 2 Apr 2025 · Verified 6 Jul 2026.
A, D and E only
B, D and E only
A, B and C only
C, D and E only
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