The formula of tetraaquadichloridochromium (III) chloride is [Cr(H2O)4Cl2]Cl.
In this complex, there is one ionizable chloride ion present outside the coordination sphere.
The dissociation reaction is:
[Cr(H2O)4Cl2]Cl→[Cr(H2O)4Cl2]++Cl−
Number of moles of the complex =M×V=0.05×1000100=0.005 moles.
Since one mole of the complex yields one mole of chloride ions, the number of moles of Cl− ions produced is 0.005 moles.
When excess AgNO3 is added, the chloride ions precipitate as AgCl:
Ag++Cl−→AgCl↓
Number of moles of AgCl precipitated =0.005=5×10−3 moles.
The value is 5.
Answer: 5