Electrons must be removed from the outermost orbital to form an ion.
The electronic configurations of the elements are as follows,
Cr24→[Ar]3d54s1;Cr2+→[Ar]3d4
Mn25→[Ar]3d54s2;Mn+→[Ar]3d54s1
Ni28→[Ar]3d84s2;Ni2+→[Ar]3d8
23V→[Ar]3d34s2;V+→[Ar]3d34s1
Hence option B is the answer.