If M+2=Co+2 then Co+2+H2 S→ Black [A] CoS+ byproduct CoS+ aqua regia →[B]CoCl2+NOCl+S+H2O CoCl2+KNO2CH3COOHk3[CO(NO2)6]+ byproduct [C]=Co+3→3d6⇒NO2 is SFL so Co +3 has zero unpaired e− ⇒n=0⇒u=n(n+2)=0B.M
Consider the following test for a group-IV cation. M2++H2 S→A (Black precipitate) + by product A+ aqua regia →B+NOCl+S+H2OB+KNO2+CH3COOH→C+ by product The spin-only magnetic moment value of the metal complex C is ______ BM (Nearest integer)
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By usual analysis, 1.00 g of compound $(\mathrm{X})$ gave 1.79 g of magnesium pyrophosphate. The percentage of phosphorus in compound $(X)$ is : (nearest integer) (Given, molar mass in $\mathrm{g} \mathrm{mol}^{-1}: \mathrm{O}=16, \mathrm{Mg}=24, \mathrm{P}=31$)
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