In the complex [Co(NH3)6]3+ Ammonia is strong field ligand and electronic configuration of
Co3+⇒3d6(t2g6,eg0)
Hybridisation: d2sp3
Pairing of electrons takes place due to the strong field ligand. Hence, it is inner orbital complex (spin paired complex).
In the complex [CoF6]3− fluoride is weak field ligand and electronic configuration of Co3+ ⇒3d6(t2g4,eg2).
Hybridisation: sp3d2
Pairing of electrons not takes place due to the weak field ligand. Hence, it is outer orbital complex (spin free complex).
Hence option B is the answer.