Since spin only magnetic moment is 4.90 BM so number of unpaired electrons must be 4. There are two possibilities:
(1) If the complex is octahedral, then it has to be high spin complex with configuration t2g2,1,1eg1,1, in that case CFSE=4×(−0.4Δ0)+2×0.6Δ0=−0.4Δ0
(2) If the complex is tetrahedral then its electronic configuration will be =egt2g2,11,1,1 and CFSE will be=3X (−0.6Δt)+3X(0.4Δt)=−0.6Δt