JEE Main 2014 — Chemistry Inorganic Chemistry

The Molecular orbital electronic configurations are

${\text{O}}_{2}^{-} \Rightarrow \text{σ}1{\text{s}}^{2} <\overset{*}{\text{σ}} 1{\text{s}}^{2} <\text{σ}2{\text{s}}^{2} <\overset{*}{\text{σ}} 2{\text{s}}^{2} <\text{σ}2{\text{p}}_{\text{z}}^{2} <\text{π}2{\text{p}}_{\text{x}}^{2} =\text{π}2{\text{p}}_{\text{y}}^{2} <\overset{*}{\text{π}} 2{\text{p}}_{\text{x}}^{2} =\overset{*}{\text{π}} 2{\text{p}}_{\text{y}}^{1}$O2−​⇒σ1s2<σ∗1s2<σ2s2<σ∗2s2<σ2pz2​<π2px2​=π2py2​<π∗2px2​=π∗2py1​ (unpaired electron)

$${\text{N}}_{2}^{ 2+ } \Rightarrow \text{σ}1{\text{s}}^{2} <\overset{*}{\text{σ}} 1{\text{s}}^{2} <\text{σ}2{\text{s}}^{2} <\overset{*}{\text{σ}} 2{\text{s}}^{2} <\text{π}2{\text{p}}_{\text{x}}^{2} =\text{π}2{\text{p}}_{\text{y}}^{2} <\text{σ}2{\text{p}}_{\text{z}}^{0}$$N22+​⇒σ1s2<σ∗1s2<σ2s2<σ∗2s2<π2px2​=π2py2​<σ2pz0​

$${\text{O}}_{2}^{ 2- } \Rightarrow \text{σ}1{\text{s}}^{2} <\overset{*}{\text{σ}} 1{\text{s}}^{2} <\text{σ}2{\text{s}}^{2} <\overset{*}{\text{σ}} 2{\text{s}}^{2} <\text{σ}2{\text{p}}_{\text{z}}^{2} <\text{π}2{\text{p}}_{\text{x}}^{2} =\text{π}2{\text{p}}_{\text{y}}^{2} <\overset{*}{\text{π}} 2{\text{p}}_{\text{x}}^{2} =\overset{*}{\text{π}} 2{\text{p}}_{\text{y}}^{2}$$O22−​⇒σ1s2<σ∗1s2<σ2s2<σ∗2s2<σ2pz2​<π2px2​=π2py2​<π∗2px2​=π∗2py2​

$${\text{N}}_{2} \Rightarrow \text{σ}1{\text{s}}^{2} <\overset{*}{\text{σ}} 1{\text{s}}^{2} <\text{σ}2{\text{s}}^{2} <\overset{*}{\text{σ}} 2{\text{s}}^{2} <\text{π}2{\text{p}}_{\text{x}}^{2} =\text{π}2{\text{p}}_{\text{y}}^{2} <\text{σ}2{\text{p}}_{\text{z}}^{2}$$N2​⇒σ1s2<σ∗1s2<σ2s2<σ∗2s2<π2px2​=π2py2​<σ2pz2​