JEE Main 2014 — Chemistry Inorganic Chemistry

2014mcqhard

The equation which is balanced and represents the correct product(s) is

Official previous-year question

Held on 6 Apr 2014 · Verified 6 Jul 2026.

Options

A
${\text{Li}}_{2} \text{O} + 2 \text{KCl} \rightarrow 2 \text{LiCl} + {\text{K}}_{2} \text{O}$
B
${[\mathrm{CoCl}{({\mathrm{NH}}_{3})}_{5}]}^{+}+5{H}^{+}\rightarrow {\mathrm{Co}}^{2+}+5{\mathrm{NH}}_{4}^{+}+{\mathrm{Cl}}^{-}$
C
${[\mathrm{Mg}{({H}_{2}O)}_{6}]}^{2+}+{(\mathrm{EDTA})}^{4-}\overset{\mathrm{excess}NaOH}{\rightarrow }{[\mathrm{Mg}(\mathrm{EDTA})]}^{2+}+6{H}_{2}O$
D
${\mathrm{CuSO}}_{4}+4\mathrm{KCN}\rightarrow {K}_{2}[\mathrm{Cu}{(\mathrm{CN})}_{4}]+{K}_{2}{\mathrm{SO}}_{4}$

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Solution

${\text{Li}}_{2} \text{O} + 2 \text{KCl} \rightarrow 2 \text{LiCl} + {\text{K}}_{2} \text{O}$ is incorrect since, $\mathrm{KCl}$ is less reactive than $\mathrm{LiCl}$ and will not form $\mathrm{LiCl}$ .

${[\mathrm{Mg}{({H}_{2}O)}_{6}]}^{2+}+{(\mathrm{EDTA})}^{4-}\overset{\mathrm{excess}NaOH}{\rightarrow }{[\mathrm{Mg}(\mathrm{EDTA})]}^{2+}+6{H}_{2}O$ is incorrect since, the charge on the complex will be $-2$ , not $+2$ .

${\mathrm{CuSO}}_{4}+4\mathrm{KCN}\rightarrow {K}_{2}[\mathrm{Cu}{(\mathrm{CN})}_{4}]+{K}_{2}{\mathrm{SO}}_{4}$ is incorrect since, the final complex formed is ${K}_{3}[\mathrm{Cu}{(\mathrm{CN})}_{4}]$ , not ${K}_{2}[\mathrm{Cu}{(\mathrm{CN})}_{4}]$ .

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Options

${\text{Li}}_{2} \text{O} + 2 \text{KCl} \rightarrow 2 \text{LiCl} + {\text{K}}_{2} \text{O}$

${[\mathrm{CoCl}{({\mathrm{NH}}_{3})}_{5}]}^{+}+5{H}^{+}\rightarrow {\mathrm{Co}}^{2+}+5{\mathrm{NH}}_{4}^{+}+{\mathrm{Cl}}^{-}$

${[\mathrm{Mg}{({H}_{2}O)}_{6}]}^{2+}+{(\mathrm{EDTA})}^{4-}\overset{\mathrm{excess}NaOH}{\rightarrow }{[\mathrm{Mg}(\mathrm{EDTA})]}^{2+}+6{H}_{2}O$

${\mathrm{CuSO}}_{4}+4\mathrm{KCN}\rightarrow {K}_{2}[\mathrm{Cu}{(\mathrm{CN})}_{4}]+{K}_{2}{\mathrm{SO}}_{4}$

Solution

JEE Main 2014 — Chemistry Inorganic Chemistry

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JEE Main 2014 — Chemistry Inorganic Chemistry

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JEE Main Inorganic Chemistry in other years

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