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Oxidation state of sulphur in anions SO_3^2-, S_2 O_4^2- and S_2 O_6^2- increases in the orders :

JEE Main 2013 — Chemistry Inorganic Chemistry

2013mcqeasy

Oxidation state of sulphur in anions SO32−,S2O42−\mathrm{SO}_3^{2-}, \mathrm{S}_2 \mathrm{O}_4^{2-}SO32−​,S2​O42−​ and S2O62−\mathrm{S}_2 \mathrm{O}_6^{2-}S2​O62−​ increases in the orders :

Official previous-year question

Held on 22 Apr 2013 · Verified 6 Jul 2026.

Options

  1. A

    S2O62−<S2O42−<SO32−\mathrm{S}_2 \mathrm{O}_6^{2-} < \mathrm{S}_2 \mathrm{O}_4^{2-} < \mathrm{SO}_3^{2-}S2​O62−​<S2​O42−​<SO32−​

  2. B

    SO62−<S2O42−<S2O62−\mathrm{SO}_6^{2-} < \mathrm{S}_2 \mathrm{O}_4^{2-} < \mathrm{S}_2 \mathrm{O}_6^{2-}SO62−​<S2​O42−​<S2​O62−​

  3. C

    S2O42−<SO32−<S2O62−\mathrm{S}_2 \mathrm{O}_4^{2-} < \mathrm{SO}_3^{2-} < \mathrm{S}_2 \mathrm{O}_6^{2-}S2​O42−​<SO32−​<S2​O62−​

  4. D

    S2O42−<S2O62−<SO32−\mathrm{S}_2 \mathrm{O}_4^{2-} < \mathrm{S}_2 \mathrm{O}_6^{2-} < \mathrm{SO}_3^{2-}S2​O42−​<S2​O62−​<SO32−​

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