vivfI=−2ghi=−2×9.8×10=−28 m/s=2ghi=2×9.8×10=14 m/s=ΔP=mvf−mvi=m[vf−vi]=0.5[14−(−28)]=0.5×42=21NS
A ball of mass 0.5 kg is dropped from a height of 40 m . The ball hits the ground and rises to a height of 10 m . The impulse imparted to the ball during its collision with the ground is (Take g=9.8 m/s2 )
Held on 30 Apr 2025 · Verified 9 Jul 2026.
21 NS
7 NS
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84 NS
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