
t1=30 min=21hr t2 VBVS=10 min=61hr= Speed of Bus = Speed of scooty (girl) (Same direction) (Opposite direction) d=(VB−VS)t1=(VB+VS)t2⇒(VB−60)21=(VB+60)613VB−180=VB+602VB=240⇒VB=120 km/hr Distance =(VB−VS)t1 D=(120−60)21=30 kmt= VBd=12030=41hr=15 min