Let the gravitational field at point Q is zero. Therefore, we can write
(x2−Gm)+((R−x)2−G×9m)=0⇒x2(R−x)2=9⇒x=4R
Now, net gravitational potential at point Q will be
Vnet=(x−Gm)+(R−x−G×9m)=(4R−Gm)+(43R−G×9m)=R−16Gm
NEET UG 2023 — Physics Mechanics
Two bodies of mass m and 9m are placed at a distance R. The gravitational potential on the line joining the bodies where the gravitational field equals zero, will be (G=gravitational constant):
Held on 30 Apr 2023 · Verified 9 Jul 2026.
−R20Gm
−R8Gm
−R12Gm
−R16Gm
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