Given,
Escape velocity from earth's surface =v
v=vearth=2gR
=34πR32GM34πR2=V2GM34πR2=38GρπR2
g= Gravitation acceleration on earth surface
R= Radius of earth
G=Universal gravitational constant
Escape velocity of another planet =?
\because {R}_{p}=4R &
ρplanet=ρearth
So we can write,
ve∝R2∝R
(ve)planet(ve)earth=RplanetRearth=4RR=41
It means,
4(ve)earth=(ve)Planet
(ve)Planet=4v