mass per unit length of the ring is
λ=2πRM
∴ Mass of remaining ring is M′=λ×43(2πR)
∴M′=43M

Moment of inertia of remaining part is
I′=M′R2=43MR2=KMR2
∴K=43
NEET UG 2021 — Physics Mechanics
From a circular ring of mass M and radius R an arc corresponding to a 90∘ sector is removed. The moment of inertia of the remaining part of the ring about an axis passing through the centre of the ring and perpendicular to the plane of the ring is K times MR2. Then the value of K is___
Held on 30 Apr 2021 · Verified 9 Jul 2026.
41
87
43
81
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