As we know that the displacement covered by particle in nthsecond is given by,
∵Snth=u+(22n−1)a
but u=0
∴sn=(22n−1)a…(1)
sn+1=[22(n+1)−1]a…(2)
Now,
equation (1) divide by equation (2)
sn+1sn=2n+12n−1
NEET UG 2021 — Physics Mechanics
A small block slides down on a smooth inclined plane, starting from rest at time t=0. Let Sn be the distance travelled by the block in the interval t=n−1 to t=n. Then, the ratio sn+1sn is:
Held on 30 Apr 2021 · Verified 9 Jul 2026.
2n2n−1
2n−12n+1
2n+12n−1
2n−12n
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