
∵ At Every pt.
KE+PE= constant
so,
(KE)A+(PE)A=(KE)B+(PE)B
0+mgS=3(PE)B+(PE)B
mgS=4mgh
h=4S
Now,
KE at pt.B−
∵ At pt.B−
KE=3PE
21mv2=34mgs
v=23gS
NEET UG 2021 — Physics Mechanics
A particle is released from height S from the surface of the Earth. At a certain height its kinetic energy is three times its potential energy. The height from the surface of the earth and the speed of the particle at that instant are respectively___
Held on 30 Apr 2021 · Verified 9 Jul 2026.
4S,23gS
4S,23gS
4S,23gS
2S,23gS
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