First, calculate the mean of observations,
⇒Am=51.25+1.24+1.27+1.21+1.28=1.25sec,
it means, \Delta {A}_{1}=|1.25-1.25|s,\Delta {A}_{2}=|1.24-1.25|s,\Delta {A}_{3}=|1.27-1.25|s, \Delta {A}_{4}=|1.21-1.25|s&\Delta {A}_{5}=|1.28-1.25|s
then calculates the mean of error,
ΔAm=50+0.01+0.02+0.04+0.03=50.1
error AmΔAm=5×1.250.1×100=1.6