Let h be the height through which the coin is dropped. Then, according to the equation of motion, it is given as h=ut+21gt2⇒t= g2 h[∵u=0]⇒t∝g1 As the elevator is moving uniformly i.e. its velocity is constant, so the acceleration is zero. ∴ Relative acceleration of the lift when it is either moving upward or downward is given as, g′=g±a=g±0=g Hence, the time for the coin to reach the floor will remains same i.e. t1=t2.
A person standing on the floor of an elevator drops a coin. The coin reaches the floor in time t_1 if the elevator is at rest and in time t_2 if the…
NEET UG 2019 — Physics Mechanics
A person standing on the floor of an elevator drops a coin. The coin reaches the floor in time t1 if the elevator is at rest and in time t2 if the elevator is moving uniformly. The which of the following option is correct?
Held on 30 Apr 2019 · Verified 9 Jul 2026.
Options
- A
t1<t2 or t1>t2 depending upon whether the lift is going up or down
- B
t1<t2
- C
t1>t2
- D
t1=t2
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