Energy of the cylinder =21mv2+21Iω2
=21mv2+212mr2r2v2
=43mv2
=43×100×(20×10−2)2
=3J
A disc of radius 2m and mass 100kg rolls on a horizontal floor. Its centre of mass has speed of 20cms−1. How much work is needed to stop it?
Held on 30 Apr 2019 · Verified 9 Jul 2026.
3J
30kJ
2J
1J
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