A body of mass m is kept on a rough horizontal surface (coefficient of friction =μ ). Horizontal force is applied on the body, but it does not move.…
NEET UG 2019 — Physics Mechanics
2019mcqmedium
A body of mass m is kept on a rough horizontal surface (coefficient of friction =μ ). Horizontal force is applied on the body, but it does not move. The resultant of normal reaction and the frictional force acting on the object is given F, where F is
Official previous-year question
Held on 30 Apr 2019 · Verified 9 Jul 2026.
Options
A
∣F∣=mg+μmg
B
∣F∣=μmg
C
∣F∣≤mg1+μ2
D
∣F∣=mg
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Solution
The situation can be drawn as
The frictional force, f=μN=μmg[∵N=mg] From Free body diagram (FBD), the resultant force is ∣F∣=N2+f2=(mg)2+(μmg)2=mg1+μ2 This is the minimum force required to move the object. But as the body is not moving ∴∣F∣≤mg1−μ2
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