By conversation of linear momentum
mv=4mv′⇒v′=4v
Coefficient of restitution (e) =VelocityofapproachVelocityofseparation
=v−04v−0=41=0.25
NEET UG 2018 — Physics Mechanics
A moving block having mass m, collides with another stationary block having mass 4m. The lighter block comes to rest after collision. When the initial velocity of the lighter block is v, then the value of coefficient of restitution (e) will be
Held on 30 Apr 2018 · Verified 9 Jul 2026.
0.8
0.25
0.5
0.4
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