At the end of 2sec, w=w0+αt
w=0+2(2)=4 rad/sec
Particle acceleration towards the center is =ac=rw2
ac=21(4)2=8 m/s2
Tangential acceleration at=α⋅R
=1m/s2
anet=ac2+at2
=82+12
=65≈8 (approximately)
NEET UG 2016 — Physics Mechanics
A uniform circular disc of radius 50 cm at rest is free to rotate about an axis which is perpendicular to its plane and passes through its centre. It is subjected to a torque which produces a constant angular acceleration of 2.0rads−2. Its net acceleration in ms−2 at the end of 2.0 s is approximately:
Held on 30 Apr 2016 · Verified 9 Jul 2026.
8.0
7.0
6.0
3.0
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