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Two particles of masses m_1, m_2 move with initial velocities u_1 and u_2. On collision, one of the particles get excited to higher level, after…

NEET UG 2015 — Physics Mechanics

2015mcqeasy

Two particles of masses m1,m2{m}_{1}, {m}_{2}m1​,m2​ move with initial velocities u1{u}_{1}u1​ and u2{u}_{2}u2​. On collision, one of the particles get excited to higher level, after absorbing energy ϵ.\epsilon .ϵ. If final velocities of particles be v1{v}_{1}v1​ and v2{v}_{2}v2​ then we must have:

Official previous-year question

Held on 30 Apr 2015 · Verified 9 Jul 2026.

Options

  1. A

    m12u1+m22u2−ϵ=m12v1+m22v2{m}_{1}^{2}{u}_{1}+{m}_{2}^{2}{u}_{2}-\epsilon ={m}_{1}^{2}{v}_{1}+{m}_{2}^{2}{v}_{2}m12​u1​+m22​u2​−ϵ=m12​v1​+m22​v2​

  2. B

    12m1u12+12m2u22=12m1v12+12m2v22−ϵ\frac{1}{2}{m}_{1}{u}_{1}^{2}+\frac{1}{2}{m}_{2}{u}_{2}^{2}=\frac{1}{2}{m}_{1}{v}_{1}^{2}+\frac{1}{2}{m}_{2}{v}_{2}^{2}-\epsilon21​m1​u12​+21​m2​u22​=21​m1​v12​+21​m2​v22​−ϵ

  3. C

    12m1u12+12m2u22−ϵ=12m1v12+12m2v22\frac{1}{2}{m}_{1}{u}_{1}^{2}+\frac{1}{2}{m}_{2}{u}_{2}^{2}-\epsilon =\frac{1}{2}{m}_{1}{v}_{1}^{2}+\frac{1}{2}{m}_{2}{v}_{2}^{2}21​m1​u12​+21​m2​u22​−ϵ=21​m1​v12​+21​m2​v22​

  4. D

    12m2u12 + 12m1u12+ ε = 12m2v12 + 12m1v12\frac{\text{1}}{\text{2}} {\text{m}}_{\text{2}} {\text{u}}_{\text{1}}^{\text{2}} \text{ + }\frac{\text{1}}{\text{2}} {\text{m}}_{\text{1}} {\text{u}}_{\text{1}}^{\text{2}} \text{+ ε = }\frac{\text{1}}{\text{2}} {\text{m}}_{\text{2}} {\text{v}}_{\text{1}}^{\text{2}} \text{ + }\frac{\text{1}}{\text{2}} {\text{m}}_{\text{1}} {\text{v}}_{\text{1}}^{\text{2}}21​m2​u12​ + 21​m1​u12​+ ε = 21​m2​v12​ + 21​m1​v12​

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