From conservation of energy initial total energy
Ei=21m1u12+21m2u22
After collision total final energy
Ef=21m1v12+21m2v22+ϵ
∴21m1u12+21m2u22=21m1v12+21m2v22+ϵ
21m1u12+21m2u22−ϵ=21m1v12+21m2v22
NEET UG 2015 — Physics Mechanics
Two particles of masses m1,m2 move with initial velocities u1 and u2. On collision, one of the particles get excited to higher level, after absorbing energy ϵ. If final velocities of particles be v1 and v2 then we must have:
Held on 30 Apr 2015 · Verified 9 Jul 2026.
m12u1+m22u2−ϵ=m12v1+m22v2
21m1u12+21m2u22=21m1v12+21m2v22−ϵ
21m1u12+21m2u22−ϵ=21m1v12+21m2v22
21m2u12 + 21m1u12+ ε = 21m2v12 + 21m1v12
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