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The position vector of a particle R as a function of time is given by: R=4 sin⁡(2π t) i+4cos⁡(2π t) j Where R is in meters, t is in seconds and i and…

NEET UG 2015 — Physics Mechanics

2015mcqeasy

The position vector of a particle R⃗\vec{R}R as a function of time is given by:

R⃗=4sin⁡(2πt)i^+4cos⁡(2πt)j^\vec{R}=4\mathrm{sin}⁡(2\pi t)\hat{i}+4cos⁡(2\pi t)\hat{j}R=4sin⁡(2πt)i^+4cos⁡(2πt)j^​

Where R is in meters, t is in seconds and i^\hat{i}i^ and j^\hat{j}j^​ denote unit vectors along x- and y-directions, respectively. Which one of the following statements is wrong for the motion of particle?

Official previous-year question

Held on 30 Apr 2015 · Verified 9 Jul 2026.

Options

  1. A

    Magnitude of acceleration vector is v2R\frac{{v}^{2}}{R}Rv2​ , where vvv is the velocity of particle

  2. B

    Magnitude of the velocity of particle is 8 meter/second

  3. C

    Patch of the particle is a circle of radius 4 meter

  4. D

    Acceleration vector is along −R⃗-\vec{R}−R

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