Skip to main content

The cylindrical tube of a spray pump has radius R , one end of which has n fine holes, each of radius r . If the speed of the liquid in the tube is V…

NEET UG 2015 — Physics Mechanics

2015mcqmedium

The cylindrical tube of a spray pump has radius RRR , one end of which has nnn fine holes, each of radius rrr . If the speed of the liquid in the tube is VVV , the speed of the ejection of the liquid through the holes is :

Official previous-year question

Held on 30 Apr 2015 · Verified 9 Jul 2026.

Options

  1. A

    VR2nr2\frac{V{R}^{2}}{n{r}^{2}}nr2VR2​

  2. B

    VR2n3r2\frac{V{R}^{2}}{{n}^{3}{r}^{2}}n3r2VR2​

  3. C

    V2Rnr\frac{{V}^{2}R}{nr}nrV2R​

  4. D

    VR2n2r2\frac{V{R}^{2}}{{n}^{2}{r}^{2}}n2r2VR2​

Did you get this right?

Sign in to track your attempts and accuracy.

Your note

Sign in to keep a private note on this question. Nothing you write is ever public.

NEET UG Mechanics in other years

More NEET UG Mechanics questions

A bullet of mass 10 g moving with 400 m/s penetrates a wall and comes to rest. The loss in kinetic energy is:

2026easy

A physical quantity $P$ is related to four observations $a, b, c$ and $d$ as follows : $P=a^3 b^2 / c \sqrt{d}$ The percentage errors of measurement in $a, b, c$ and $d$ are $1 \%, 3 \%, 2 \%$ and $4 \%$ respectively. The percentage error in the quantity $P$ is

2025medium

A uniform rod of mass 20 kg and length 5 m leans against a smooth vertical wall making an angle of $60^{\circ}$ with it. The other end rests on a rough horizontal floor. The friction force that the floor exerts on the rod is (take $\mathrm{g}=10 \mathrm{~m} / \mathrm{s}^2$ )

2025medium

The radius of Martian orbit around the Sun is about 4 times the radius of the orbit of Mercury. The Martian year is 687 Earth days. Then which of the following is the length of 1 year on Mercury?

2025medium

Consider a water tank shown in the figure. It has one wall at $x=L$ and can be taken to be very wide in the $z$ direction. When filled with a liquid of surface tension $S$ and density $\rho$, the liquid surface makes angle $\theta_0\left(\theta_0 \ll 1\right)$ with the $x$-axis at $x=L$. If $y(x)$ is the height of the surface then the equation for $y(x)$ is: ![NEET 2025 Physics, Mechanical Properties of Fluids — question figure](https://prepforbharat.s3.ap-south-1.amazonaws.com/exam/616059730283de43c87e3e22/Physics/images/Mechanical_Properties_of_Fluids/682c9a92c2281abe1696a0a1/question_1__q_682c9a92c2281abe1696a0a1__cdn-question-pool.getmarks.app__apNa77tO8zggC1qbUK0Cc-__LAswz6bHpIOciKbseBc.original.fullsiz__2ce9bc34e2_final_ppt_sync.png) $\left(\operatorname{take} \theta(x)=\sin \theta(x)=\tan \theta(x)=\frac{d y}{d x}, g\right.$ is the acceleration due to gravity)

2025hard

Other Physics topics for NEET UG

Keep practicing Mechanics

Work through every NEET UG Mechanics PYQ, year by year.

Browse all Physics topics