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A particle undergoes a one-dimensional motion such that its velocity varies according to v(x)=β x^-2n, where β and n are constants and x is the…

NEET UG 2015 — Physics Mechanics

2015mcqmedium

A particle undergoes a one-dimensional motion such that its velocity varies according to v(x)=βx−2nv(x)=\beta {x}^{-2n}v(x)=βx−2n, where β\betaβ and n\text{n}n are constants and xxx is the position of the particle. The acceleration of the particle as a function of xxx is given by

Official previous-year question

Held on 30 Apr 2015 · Verified 9 Jul 2026.

Options

  1. A

    −2nβ2x−2n−1-2n{\beta }^{2}{x}^{-2n-1}−2nβ2x−2n−1

  2. B

    −2nβ2x−4n−1-2n{\beta }^{2}{x}^{-4n-1}−2nβ2x−4n−1

  3. C

    −2nβ2x−2n+1-2n{\beta }^{2}{x}^{-2n+1}−2nβ2x−2n+1

  4. D

    −2nβ2x−4n+1-2n{\beta }^{2}{x}^{-4n+1}−2nβ2x−4n+1

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