
kinetic energy of the ball on reaching ground
KE1=mgh+21mv02
after collision 2KE1=mgh
2mgh+21mv02=mgh
v0=2gh=20ms−1
NEET UG 2015 — Physics Mechanics
A ball is thrown vertically downwards from a height of 20m with an initial velocity v0. It collides with the ground, loses 50 percent of its energy in collision and rebounds to the same height. The initial velocity v0 is: (Take g=10ms−2)
Held on 30 Apr 2015 · Verified 9 Jul 2026.
20ms−1
28ms−1
10ms−1
14ms−1
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