Here we have to find the graph between (E) and (r) in the given situation.
We know that,
E=−R3GM×r(ifr<R) So, E is directly proportional to r and there is a negative sign. Hence graph will be straight line in 2nd quadrant starting from origin like the case of uniform motion in negative direction.
E=−r3GM×r(ifr≥R)So, E is inversly proportional tor2 and there is a negative sign. Hence graph will be like as shown in this figure.



