According to question the light is unable to escape the gravitational pull of the black hole thus the escape velocity is equal to the speed of the light so,
Escape velocity is Ve=C.
We know that escape velocity is given by,
R2GM=3×108
Putting in the values we get,
⇒R2×(320×10−11)(6×1024)=3×108
Thus, on solving we get,
R≈9mm≈10−2m