M.J. of D1 is I1=2MR2=22(0.2)2 =0.04 kg m2 initial angular velocity of D1 is ω1=50radS−1 M.J of D2 is I2=24×(0.1)2=0.02 kgm2 initial angular velocity of D2 is ω2= 200 and S−1. According to the law of conservation of angular moment L1=L2∴I1ω1+I2ω2=(I1+I2)⇒ω=I1+1l1w1+l2w2∴ω=0.04+0.02(0.04)2×50+(0.02)2×200=0.062+4=100rads−1