Here, P=cda3b2 ∴PΔP===×100=(a3Δa+b2Δb+cΔc+dΔd′)×1003aΔa×100+2bΔb×100+cΔc×100+dΔd′×1003×1+2×2+3+43+4+3+4=14%
NEET UG 2013 — Physics Mechanics
In an experiment four quantities a,b,c and d are measured with percentage error 1%,2%,3% and 4% respectively. Quantity P is calculated as follows P=cda3b2%, Error in P is
Held on 30 Apr 2013 · Verified 9 Jul 2026.
14%
10%
7%
4%
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