Given, force F=3i+j r1=(2i+k)m and r2=(4i+3j−k)m∴s=r2−r1=(4i+3j−k)−(2i+k)=(2i+3j−2k)m∴W=F⋅s=(3i+j)⋅(2i+3j−2k)=3×2+3+0=6+3=9 J
A uniform force of (3 i+ j) N acts on a particle of mass 2 ~kg. Hence the particle is displaced from position (2 i+ k) m to position (4 i+3 j- k) m.…
NEET UG 2013 — Physics Mechanics
A uniform force of (3i+j)N acts on a particle of mass 2 kg. Hence the particle is displaced from position (2i+k)m to position (4i+3j−k)m. The work done by the force on the particle is
Held on 30 Apr 2013 · Verified 9 Jul 2026.
Options
- A
9 J
- B
6 J
- C
13 J
- D
15 J
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