The position vector of centre of mass r=m1+m2m1r1+m2r2=1+31(i^+2j^+k^)+3(−3i^−2j^+k^)=41(−8i^−4j^+4k^)=−2i^−j^+k^ The centre of mass changes its position only under the translatory motion. There is no effect of rotatory motion on centre of mass of the body.
Two bodies of mass 1 ~kg and 3 ~kg have position vectors i+2 j+ k and -3 i-2 j+ k, respectively. The centre of mass of this system has a position…
NEET UG 2009 — Physics Mechanics
Two bodies of mass 1 kg and 3 kg have position vectors i^+2j^+k^ and −3i^−2j^+k^, respectively. The centre of mass of this system has a position vector
Held on 30 Apr 2009 · Verified 9 Jul 2026.
Options
- A
−2i^+2k^
- B
−2i^−j^+k^
- C
2i^−j^−2k^
- D
−i^+j^+k^
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