Key Idea Apply law of conservation of linear momentum. Momentum of first part =1×12=12 kg ms−1 Momentum of the second part =2×8=16 kg ms−1 ∴ Resultant momentum =(12)2+(16)2=20 kg ms−1 The third part should also have the same momentum. Let the mass of the third part be, then 4×MM=20=5 kg Alternative : 
MvcosθMvsinθtanθM=12=16=1216=34=4×312×5=1260=5 kg