Key Idea If the particle is moving in a straight line under the action of a constant force then distance covered s=ut+21 at 2. Since the body start from rest u=0 ∴s=21at2 Now, s1=21a(10)2 and s2=21a(20)2 Dividing Eq. (i) and Eq. (ii), we get s2s1⇒s2=(20)2(10)2=4 s1