Let y be the relative velocity of scooter(s) w.r.t. bus (B), then 
∴vS Relative velocity =v+vB= displacement / time =1001000=10 ms−1 Now, substituting the value of in Eq. (i), we get vS=10+10=20 ms−1
NEET UG 2009 — Physics Mechanics
A bus is moving with a speed of 10 ms−1 on a straight road. A scooterist wishes to overtake the bus in 100 s. If the bus is at a distance of 1 km from the scooterist, with what speed should the scooterist chase the bus?
Held on 30 Apr 2009 · Verified 9 Jul 2026.
20 ms−1
40 ms−1
25 ms−1
10 ms−1
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