Distance travelled by the particle in nth second is Snth=u+21a(2n−1) where u is initial speed and a is acceleration of the particle. Here, n=3,u=0,a=34 m/s2 ∴S3 rd =0+21×34×(2×3−1)=64×5=310 m Alternative : Distance travelled in the 3rd second = distance travelled in 3 s - distance travelled in 2 s As, u=0, S(3rds)=21a⋅32−21a⋅22=21⋅a⋅5 Given a=34 ms−2 ∴S(3rds)=21×34×5=310 m