Key Idea: In the given problem conservation of linear momentum and energy hold good. Conservation of momentum yields. m1v1+m2y2=0or 4y1+0.2y2=0 Conservation of energy yields 21m1y12+21m2y22=1050or 21×4y12+21×0.2×y22=1050or 2v12+0.1v22=1050 Solving Eqs. (i) and (ii), we have v1=100 m/s