Balancing the forces, we get Mg−N=MRv2 For weightlessness, N=0 ∴RMv2=Mg where R is the radius of curvature and v is the speed of car. Therefore, v=Rg Putting the values, R=20 m,g=10.0 m/s2 So, y=20×10.0=14.14 m/s2 Thus, the speed of the car at the top of the hill is between 14 m/s and 15 m/s. Note: The roller coaster is a popular amusement ride developed for amusement parks and modern theme parks.