Key Idea : The problem requires kinematics equations of motion. Let u and v be the first and final velocities of particle and a&s be the constant acceleration and distance covered by it. From third equation of motion y2=u2+2as⇒(20)2=(10)2+2a×135or a=2×135300=910 ms−2 Now using first equation of motion, v=u+ator t=av−u=(10/9)20−10=1010×9=9 s