Given, I=2 kg−m2, ω0=6060×2πrad/s ω0 and t=60 s The torque required to stop the wheel's rotation is ττ=I∝l(tω0−ω)=60×602×2π×60=15π N−m
A wheel having moment of inertia 2 kg m2 about its vertical axis, rotates at the rate of 60rpm about the axis. The torque which can stop the wheel's rotation in one minute would be:
Held on 30 Apr 2004 · Verified 9 Jul 2026.
152π N−m
12π N−m
15π5 N−m
18π N−m
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