We know that K.E. =2mP2 ∴⇒E2E1=m1m2E2E1=P22/2m2P12/2m1 Here m1=m2 ∴E1<E2
A particle of mass m_1 is moving with a velocity v_1 and another particle of mass m_2 is moving with a velocity v_2. Both of them have the same…
NEET UG 2004 — Physics Mechanics
A particle of mass m1 is moving with a velocity v1 and another particle of mass m2 is moving with a velocity v2. Both of them have the same momentum but their different kinetic energies are E1 and E2 respectively. If m1>m2 then:
Held on 30 Apr 2004 · Verified 9 Jul 2026.
Options
- A
E1<E2
- B
E2E1=m1m1
- C
E1>E2
- D
E1=E2
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