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The electric field in a plane electromagnetic wave is given by E_z=60 cos (5 x+1.5 × 10^9 t ) V / m . Then expression for the corresponding magnetic…

NEET UG 2025 — Physics Electromagnetism

2025mcqmedium

The electric field in a plane electromagnetic wave is given by Ez=60cos⁡(5x+1.5×109t)V/m.E_z=60 \cos \left(5 \mathrm{x}+1.5 \times 10^9 \mathrm{t}\right) \mathrm{V} / \mathrm{m} .Ez​=60cos(5x+1.5×109t)V/m. Then expression for the corresponding magnetic field is (here subscripts denote the direction of the field) :

Official previous-year question

Held on 30 Apr 2025 · Verified 9 Jul 2026.

Options

  1. A

    By=2×10−7cos⁡(5x+1.5×109t)TB_y=2 \times 10^{-7} \cos \left(5 x+1.5 \times 10^9 t\right) TBy​=2×10−7cos(5x+1.5×109t)T

  2. B

    Bx=2×10−7cos⁡(5x+1.5×109t)TB_x=2 \times 10^{-7} \cos \left(5 x+1.5 \times 10^9 t\right) TBx​=2×10−7cos(5x+1.5×109t)T

  3. C

    Bz=60cos⁡(5x+1.5×109t)TB_z=60 \cos \left(5 x+1.5 \times 10^9 t\right) TBz​=60cos(5x+1.5×109t)T

  4. D

    By=60sin⁡(5x+1.5×109t)TB_y=60 \sin \left(5 x+1.5 \times 10^9 t\right) TBy​=60sin(5x+1.5×109t)T

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