Time period of oscillation of magnet inside the magnetic field T=2πMB1 T=nt=1010=1 s 1=2ππ2×1.0×10−2×B10−6 41=B10−4⇒B=0.4mT
NEET UG 2024 — Physics Electromagnetism
2024mcqmedium
The magnetic moment and moment of inertia of a magnetic needle as shown are, respectively, 1.0×10−2 A m and π210−6 kg m2. If it completes 10 oscillations in 10 s , the magnitude of the magnetic field is 
Official previous-year question
Held on 30 Apr 2024 · Verified 9 Jul 2026.
Options
- A
0.4 T
- B
4 T
- C
0.4 mT
- D
4 mT
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