x8=40−x12 x2=40−x3 80−2x=3x 16=x from B =40−16=24 cm 
NEET UG 2024 — Physics Electromagnetism
The given circuit shows a uniform straight wire AB of 40 cm length fixed at both ends. In order to get zero reading in the galvanometer G, the free end of J is to be placed from B at: 
Held on 30 Apr 2024 · Verified 9 Jul 2026.
32 cm
8 cm
16 cm
24 cm
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