VL leads current / by 2π VL=V0sin(ωt+2π)(∵I=I0sinωt) V0=I0XL ⇒VL=10XLcos(ωt)=10ωLcos(ωt)
In the circuit shown below, the inductance L is connected to an ac source. The current flowing in the circuit is I=I_0 sin ω t. The voltage drop (V_L…
NEET UG 2024 — Physics Electromagnetism
In the circuit shown below, the inductance L is connected to an ac source. The current flowing in the circuit is I=I0sinωt. The voltage drop (VL) across L is 
Held on 30 Apr 2024 · Verified 9 Jul 2026.
Options
- A
ωLl0sinωt
- B
ωLI0sinωt
- C
ωLI0cosωt
- D
ωLI0cosωt
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